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What is the minimum value of (\sin \theta-\cos \theta)?(\sin \theta-\cos \theta) का न्यूनतम मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (-\sqrt{2})(-\sqrt{2})
The amplitude of ( \sin \theta-\cos \theta) is ( \sqrt{1^2+(-1)^2}=\sqrt{2}). In exams the minimum is the negative amplitude.(\sin \theta-\cos \theta) का amplitude (\sqrt{1^2+(-1)^2}=\sqrt{2}) है। परीक्षा में minimum हमेशा negative amplitude होगा।
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