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What is the maximum value of \(\sin \theta+\cos \theta\)?\(\sin \theta+\cos \theta\) का अधिकतम मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\sqrt{2}\)\(\sqrt{2}\)
\( \sin \theta+\cos \theta=\sqrt{2}\sin\left(\theta+\frac{\pi}{4}\right)\), so the maximum is \( \sqrt{2}\). In exams use maximum of (a\sin x+b\cos x) as \( \sqrt{a^2+b^2}\).\(\sin \theta+\cos \theta=\sqrt{2}\sin\left(\theta+\frac{\pi}{4}\right)\), इसलिए अधिकतम \(\sqrt{2}\) है। परीक्षा में (a\sin x+b\cos x) का maximum \(\sqrt{a^2+b^2}\) लें।
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