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If (\sin \theta+\cos \theta=\sqrt{2}) and (0<\theta<\frac{\pi}{2}), what is the value of (\theta)?यदि (\sin \theta+\cos \theta=\sqrt{2}) और (0<\theta<\frac{\pi}{2}), तो (\theta) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{\pi}{4})(\frac{\pi}{4})
In the first quadrant, the maximum of ( \sin \theta+\cos \theta) is ( \sqrt{2}) at ( \theta=\frac{\pi}{4}). In exams use symmetry.प्रथम चतुर्थांश में (\sin \theta+\cos \theta) का अधिकतम (\sqrt{2}) (\theta=\frac{\pi}{4}) पर होता है। परीक्षा में symmetry का उपयोग करें।
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