0 reads0 ratings0 helpful
What is the simplified value of (\frac{1-\sin^2 \theta}{\cos^2 \theta}), when (\cos \theta\neq0)?(\frac{1-\sin^2 \theta}{\cos^2 \theta}) का सरल मान क्या है, जब (\cos \theta\neq0)?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (1)(1)
Because (1-\sin^2 \theta=\cos^2 \theta), the value is (1). In exams replace the numerator using the basic identity.क्योंकि (1-\sin^2 \theta=\cos^2 \theta), इसलिए मान (1) होगा। परीक्षा में basic identity से numerator बदलें।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
