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If (\theta) is in the second quadrant and (\cos \theta=-\frac{3}{5}), what is (\sin \theta)?यदि (\theta) द्वितीय चतुर्थांश में है और (\cos \theta=-\frac{3}{5}), तो (\sin \theta) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{4}{5})(\frac{4}{5})
( \sin^2 \theta=1-\cos^2 \theta=\frac{16}{25}), and (\sin \theta) is positive in the second quadrant. In exams ASTC rule helps.(\sin^2 \theta=1-\cos^2 \theta=\frac{16}{25}) और द्वितीय चतुर्थांश में (\sin \theta) धनात्मक है। परीक्षा में ASTC नियम काम आता है।
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