If (\sec x-\tan x=\frac{2}{5}), what is the value of (\tan x)?यदि (\sec x-\tan x=\frac{2}{5}), तो (\tan x) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{21}{20})(\frac{21}{20})
Since ((\sec x-\tan x)(\sec x+\tan x)=1), (\sec x+\tan x=\frac{5}{2}). Subtracting the two equations gives (\tan x=\frac{21}{20}).क्योंकि ((\sec x-\tan x)(\sec x+\tan x)=1), इसलिए (\sec x+\tan x=\frac{5}{2})। दोनों समीकरण घटाने पर (\tan x=\frac{21}{20}) मिलता है।
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