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If (\sin x-\cos x=\frac{1}{3}), what is the value of (\tan x+\cot x)?यदि (\sin x-\cos x=\frac{1}{3}), तो (\tan x+\cot x) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{9}{4})(\frac{9}{4})
Squaring gives (1-2\sin x\cos x=\frac{1}{9}). Thus (\sin x\cos x=\frac{4}{9}) and (\tan x+\cot x=\frac{9}{4}).वर्ग करने पर (1-2\sin x\cos x=\frac{1}{9}) मिलता है। इसलिए (\sin x\cos x=\frac{4}{9}) और (\tan x+\cot x=\frac{9}{4})।
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