If (\cot x=\frac{3}{2}), what is the value of (\frac{\cot^2 x-1}{\cot^2 x+1})?यदि (\cot x=\frac{3}{2}), तो (\frac{\cot^2 x-1}{\cot^2 x+1}) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{5}{13})(\frac{5}{13})
Substitute (\cot^2 x=\frac{9}{4}) and simplify. The value is (\frac{\frac{9}{4}-1}{\frac{9}{4}+1}=\frac{5}{13}).(\cot^2 x=\frac{9}{4}) रखकर सरल करें। मान (\frac{\frac{9}{4}-1}{\frac{9}{4}+1}=\frac{5}{13}) है।
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