If (x) is in the second quadrant and (\sec x=-\frac{17}{8}), what is the value of (\sin x)?यदि (x) दूसरे चतुर्थांश में है और (\sec x=-\frac{17}{8}), तो (\sin x) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{15}{17})(\frac{15}{17})
(\cos x=-\frac{8}{17}). In the second quadrant, (\sin x) is positive, so (\sin x=\frac{15}{17}).(\cos x=-\frac{8}{17}) होगा। दूसरे चतुर्थांश में (\sin x) धनात्मक है, इसलिए (\sin x=\frac{15}{17}) है।
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