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If (x) is in the third quadrant and (\sin x=-\frac{5}{13}), what is the value of (\sec x)?यदि (x) तीसरे चतुर्थांश में है और (\sin x=-\frac{5}{13}), तो (\sec x) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: -(\frac{13}{12}) / (-\frac{13}{12})-(\frac{13}{12}) / (-\frac{13}{12})
In the third quadrant, (\cos x) is negative. Since (\cos x=-\frac{12}{13}), (\sec x=-\frac{13}{12}).तीसरे चतुर्थांश में (\cos x) ऋणात्मक होता है। (\cos x=-\frac{12}{13}), इसलिए (\sec x=-\frac{13}{12}) है।
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