If (\sin x+\cos x=\frac{6}{5}), what is the value of the square of (\sin x-\cos x)?यदि (\sin x+\cos x=\frac{6}{5}), तो (\sin x-\cos x) के वर्ग का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{14}{25})(\frac{14}{25})
Use the identity ((\sin x+\cos x)^2+(\sin x-\cos x)^2=2). Hence the value is (2-\frac{36}{25}=\frac{14}{25}).पहचान ((\sin x+\cos x)^2+(\sin x-\cos x)^2=2) का उपयोग करें। इसलिए मान (2-\frac{36}{25}=\frac{14}{25}) है।
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