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If (\sin x+\cos x=\frac{3}{2}), what is the value of ((\sin x-\cos x)^2)?यदि (\sin x+\cos x=\frac{3}{2}), तो ((\sin x-\cos x)^2) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{7}{4})(\frac{7}{4})
First, ((\sin x+\cos x)^2=1+2\sin x\cos x) gives (\sin x\cos x=\frac{5}{8}). Then ((\sin x-\cos x)^2=1-2\sin x\cos x=\frac{7}{4}).पहले ((\sin x+\cos x)^2=1+2\sin x\cos x) से (\sin x\cos x=\frac{5}{8}) मिलता है। फिर ((\sin x-\cos x)^2=1-2\sin x\cos x=\frac{7}{4})।
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