0 reads0 ratings0 helpful
What is the simplified value of (\frac{1+\tan^2 x}{1+\cot^2 x})?(\frac{1+\tan^2 x}{1+\cot^2 x}) का सरल मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\tan^2 x)(\tan^2 x)
The numerator is (1+\tan^2 x=\sec^2 x) and the denominator is (1+\cot^2 x=\cosec^2 x). Their ratio is (\frac{\sec^2 x}{\cosec^2 x}=\tan^2 x).ऊपर (1+\tan^2 x=\sec^2 x) और नीचे (1+\cot^2 x=\cosec^2 x) है। अनुपात (\frac{\sec^2 x}{\cosec^2 x}=\tan^2 x) होता है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
