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If (\sin^2 x=\frac{1}{4}) and (x) is in the first quadrant, what is the value of (\cos x)?यदि (\sin^2 x=\frac{1}{4}) और (x) प्रथम चतुर्थांश में है, तो (\cos x) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{\sqrt{3}}{2})(\frac{\sqrt{3}}{2})
(\cos^2 x=1-\frac{1}{4}=\frac{3}{4}). In the first quadrant, (\cos x=\frac{\sqrt{3}}{2}) is taken.(\cos^2 x=1-\frac{1}{4}=\frac{3}{4}) होगा। प्रथम चतुर्थांश में (\cos x=\frac{\sqrt{3}}{2}) लिया जाता है।
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