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If (x) is in the third quadrant and (\tan x=\frac{9}{40}), what is the value of (\sec x)?यदि (x) तीसरे चतुर्थांश में है और (\tan x=\frac{9}{40}), तो (\sec x) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (-\frac{41}{40})(-\frac{41}{40})
From (\sec^2 x=1+\tan^2 x), (|\sec x|=\frac{41}{40}). In the third quadrant, (\sec x) is negative.(\sec^2 x=1+\tan^2 x) से (|\sec x|=\frac{41}{40}) मिलता है। तीसरे चतुर्थांश में (\sec x) ऋणात्मक होता है।
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