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What is the minimum value of \(\cos^2 \theta\)?

Answer and explanation

Correct answer: \(0\)

For every real \(\theta\), \(-1 \leq \cos\theta \leq 1\). Hence, \(\cos^2\theta\) lies in the interval from \(0\) to \(1\). When \(\cos\theta=0\), for example at \(\theta=\frac{\pi}{2}\), we get \(\cos^2\theta=0\). Therefore, the minimum value is \(0\). The value \(1\) is the maximum, not the minimum. Exam tip: the square of a real number cannot be negative.

Related tags

Trigonometric FunctionsCosine FunctionTrigonometric RangeSquared FunctionsReal ValuesTrigonometric Functions And Their PropertiesMathematicsClass 12 Mcq

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