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What is the principal angle of (-\frac{41\pi}{10}) in ([0,2\pi))?(-\frac{41\pi}{10}) का ([0,2\pi)) में प्रधान कोण क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{19\pi}{10})(\frac{19\pi}{10})
Adding (2\pi) three times to (-\frac{41\pi}{10}) gives (\frac{19\pi}{10}). In exams, keep adding (2\pi) until the angle enters the interval.(-\frac{41\pi}{10}) में (3) बार (2\pi) जोड़ने पर (\frac{19\pi}{10}) मिलता है। परीक्षा में सीमा पूरी होने तक (2\pi) जोड़ें।
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