0 reads0 ratings0 helpful
If a ray turns (\frac{7}{3}) complete revolutions clockwise from the positive (x)-axis then what is the principal positive angle?यदि किरण धनात्मक (x)-अक्ष से (\frac{7}{3}) पूर्ण चक्कर दक्षिणावर्त घूमे तो मुख्य धनात्मक कोण क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{4\pi}{3})(\frac{4\pi}{3})
The clockwise angle is (-\frac{14\pi}{3}). Adding (6\pi) gives the principal angle (\frac{4\pi}{3}).दक्षिणावर्त कोण (-\frac{14\pi}{3}) है। इसमें (6\pi) जोड़ने पर (\frac{4\pi}{3}) मुख्य कोण मिलता है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
