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A ray first turns (\frac{17\pi}{6}) counterclockwise and then (\frac{5\pi}{3}) clockwise. What is the final principal angle?एक किरण पहले (\frac{17\pi}{6}) वामावर्त और फिर (\frac{5\pi}{3}) दक्षिणावर्त घूमती है। अंतिम मुख्य कोण क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{7\pi}{6})(\frac{7\pi}{6})
The net angle is (\frac{17\pi}{6}-\frac{5\pi}{3}=\frac{7\pi}{6}). Take counterclockwise as positive and clockwise as negative.नेट कोण (\frac{17\pi}{6}-\frac{5\pi}{3}=\frac{7\pi}{6}) है। वामावर्त को धनात्मक और दक्षिणावर्त को ऋणात्मक लें।
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