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What is the principal radian angle for a rotation of (-\frac{11}{8}) revolution?(-\frac{11}{8}) चक्कर के घूर्णन का मुख्य रेडियन कोण क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{5\pi}{4})(\frac{5\pi}{4})
The rotation is (-\frac{11}{8}\times2\pi=-\frac{11\pi}{4}), and adding (4\pi) gives (\frac{5\pi}{4}). In exams, first convert revolutions into radians.घूर्णन (-\frac{11}{8}\times2\pi=-\frac{11\pi}{4}) है और (4\pi) जोड़ने पर (\frac{5\pi}{4}) मिलता है। परीक्षा में चक्कर को पहले रेडियन में बदलें।
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