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What is the central angle of a sector with radius (9) cm and area (45\pi) sq cm?त्रिज्या (9) सेमी और क्षेत्रफल (45\pi) वर्ग सेमी वाले त्रिज्यखंड का केंद्रीय कोण क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{10\pi}{9})(\frac{10\pi}{9})
Put (\frac{1}{2}r^2\theta=45\pi). From (\frac{81}{2}\theta=45\pi) we get (\theta=\frac{10\pi}{9}).(\frac{1}{2}r^2\theta=45\pi) रखें। (\frac{81}{2}\theta=45\pi) से (\theta=\frac{10\pi}{9}) मिलता है।
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