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If an angle is −25π/6 radians, in which quadrant does its terminal side lie?यदि कोण −25π/6 रेडियन है, तो उसकी अंतिम भुजा किस चतुर्थांश में होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Fourth quadrantचौथा चतुर्थांश
Add 2π = 12π/6 twice to obtain a coterminal angle: −25π/6 + 24π/6 = −π/6. Adding another 2π gives 11π/6, which lies in the fourth quadrant.सह-प्रारंभिक कोण पाने के लिए 2π = 12π/6 दो बार जोड़ें: −25π/6 + 24π/6 = −π/6। इसमें एक और 2π जोड़ने पर 11π/6 मिलता है, जो चौथे चतुर्थांश में है।
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