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An angle measures \(765^\circ\). In which quadrant does its terminal side lie?एक कोण का माप \(765^\circ\) है। इसकी अंतिम भुजा किस चतुर्थांश में होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: First quadrantपहला चतुर्थांश
Subtract two full turns: \(765^\circ-2(360^\circ)=45^\circ\). Since \(45^\circ\) lies between \(0^\circ\) and \(90^\circ\), the terminal side is in the first quadrant.दो पूरे चक्कर घटाएँ: \(765^\circ-2(360^\circ)=45^\circ\)। चूँकि \(45^\circ\), \(0^\circ\) और \(90^\circ\) के बीच है, इसलिए अंतिम भुजा पहले चतुर्थांश में होगी।
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