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If ( \theta=\frac{14\pi}{5} ), what is the principal coterminal angle of ( \theta-\pi )?यदि ( \theta=\frac{14\pi}{5} ) है तो ( \theta-\pi ) का मुख्य सहसमापी कोण क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \frac{9\pi}{5} )( \frac{9\pi}{5} )
( \theta-\pi=\frac{14\pi}{5}-\frac{5\pi}{5}=\frac{9\pi}{5} ), and it is in (0) to (2\pi). First subtract and then check the range.( \theta-\pi=\frac{14\pi}{5}-\frac{5\pi}{5}=\frac{9\pi}{5} ) है और यह (0) से (2\pi) में है। पहले घटाव करें फिर सीमा देखें।
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