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In which interval does the principal coterminal angle of ( -\frac{23\pi}{10} ) lie?किस अंतराल में ( -\frac{23\pi}{10} ) का मुख्य सहसमापी कोण स्थित है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \frac{3\pi}{2}<\theta<2\pi )( \frac{3\pi}{2}<\theta<2\pi )
( -\frac{23\pi}{10}+\frac{40\pi}{10}=\frac{17\pi}{10} ), which lies between ( \frac{3\pi}{2} ) and (2\pi). First find the principal angle.( -\frac{23\pi}{10}+\frac{40\pi}{10}=\frac{17\pi}{10} ) है जो ( \frac{3\pi}{2} ) और (2\pi) के बीच है। पहले मुख्य कोण निकालें।
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