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If (r=9) cm and the sector area is ( \frac{81\pi}{8} ) square cm, what is the central angle in degrees?यदि (r=9) सेमी और त्रिज्यखंड का क्षेत्रफल ( \frac{81\pi}{8} ) वर्ग सेमी है तो केंद्र कोण डिग्री में क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (45^\circ)(45^\circ)
From ( \frac{81\pi}{8}=\frac{1}{2}\times81\times\theta ), ( \theta=\frac{\pi}{4}=45^\circ ). The angle from the sector area formula is in radians.( \frac{81\pi}{8}=\frac{1}{2}\times81\times\theta ) से ( \theta=\frac{\pi}{4}=45^\circ ) है। क्षेत्रफल सूत्र में कोण रेडियन में निकलता है।
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