If ( \theta=\frac{31\pi}{8} ), what is its reference angle?यदि ( \theta=\frac{31\pi}{8} ) है तो इसका संदर्भ कोण क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \frac{\pi}{8} )( \frac{\pi}{8} )
( \frac{31\pi}{8}-\frac{16\pi}{8}=\frac{15\pi}{8} ) and the reference angle is (2\pi-\frac{15\pi}{8}=\frac{\pi}{8}). First find the principal angle.( \frac{31\pi}{8}-\frac{16\pi}{8}=\frac{15\pi}{8} ) और संदर्भ कोण (2\pi-\frac{15\pi}{8}=\frac{\pi}{8}) है। पहले मुख्य कोण निकालें।
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