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On (A={1,2,3,4}), (R={(a,b):a^2+b^2=17}). What is (R)?समुच्चय (A={1,2,3,4}) पर (R={(a,b):a^2+b^2=17}) है। (R) कैसा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Symmetricसममित
Step 1: If (a^2+b^2=17), then (b^2+a^2=17) also holds. Step 2: Changing the order of addition does not change the sum, so the reverse pair also belongs to the relation. Step 3: Conditions involving sums of squares are often symmetric because order does not matter.चरण 1: यदि (a^2+b^2=17), तो (b^2+a^2=17) भी होगा। चरण 2: जोड़ का क्रम बदलने से योग नहीं बदलता, इसलिए उल्टा युग्म भी संबंध में है। चरण 3: वर्गों के योग जैसी शर्तें अक्सर सममित होती हैं क्योंकि उनमें क्रम का प्रभाव नहीं होता।
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