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How many symmetric relations can be formed on A = {1, 2, 3}?

Answer and explanation

Correct answer: 2⁶

For a symmetric relation on an n-element set, each diagonal pair (a,a) can be selected independently, giving n choices of position. For each unordered pair of distinct elements, either both ordered pairs are included or both are excluded. There are n(n−1)/2 such unordered pairs, so the total number of independent choices is n + n(n−1)/2 = n(n+1)/2. For n = 3, this is 3 + 3 = 6, giving 2⁶ relations. Hence option B is correct.

Related tags

Symmetric RelationCounting RelationsRelations And Functions

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