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If R is symmetric, which statement about A×A−R is correct?

Answer and explanation

Correct answer: It will also be symmetric

Let S=(A×A)−R be the complement of R in A×A. To test symmetry, assume (a,b)∈S, so (a,b)∉R. If (b,a) were in R, then symmetry of R would imply (a,b)∈R, contradicting the assumption. Therefore (b,a)∉R and hence (b,a)∈S. Thus S is symmetric. The complement need not be empty or diagonal-only, and it can be symmetric even when R is neither universal nor empty.

Related tags

Complement RelationSymmetric RelationProof By Contradiction

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