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A set (A) has (n) elements. Which is the correct formula for the number of symmetric relations on (A)?

Answer and explanation

Correct answer: (2^{\frac{n(n+1)}{2}})

Step 1: The (n) diagonal pairs can be chosen independently. Step 2: Off-diagonal pairs are chosen in reverse-pair groups, and there are (\frac{n(n-1)}{2}) such groups. Step 3: The total independent choices are (n+\frac{n(n-1)}{2}=\frac{n(n+1)}{2}).

Related tags

FormulaCounting Symmetric RelationsClass 12ExpertSymmetric RelationRelations And FunctionsMathematicsClass 12 Mcq

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