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A set (A) has (6) elements. How many relations on (A) are both symmetric and reflexive?

Answer and explanation

Correct answer: (2^{15})

Step 1: Reflexivity forces all diagonal pairs to be included. Step 2: For symmetry, we choose from (n(n-1)/2) unordered off-diagonal pair groups, so the count is (2^{\frac{6\cdot5}{2}}=2^{15}). Step 3: When reflexivity is fixed, do not count diagonal choices separately.

Related tags

Counting RelationsSymmetric And ReflexiveClass 12ExpertSymmetric RelationRelations And FunctionsMathematicsClass 12 Mcq

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