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If (A) has (4) elements, how many symmetric relations are not reflexive?

Answer and explanation

Correct answer: (2^{10}-2^6)

Step 1: The total number of symmetric relations on four elements is (2^{\frac{4\cdot5}{2}}=2^{10}). Step 2: Reflexive and symmetric relations require all four diagonal pairs, leaving (2^6) choices. Step 3: Hence symmetric but not reflexive relations are (2^{10}-2^6).

Related tags

Counting Symmetric RelationsNot ReflexiveHardSymmetric RelationRelations And FunctionsMathematicsClass 12 Mcq

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