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How many symmetric relations can be formed on a set having three elements?

Answer and explanation

Correct answer: (2^6)

Step 1: The number of symmetric relations on a set with (n) elements is (2^{\frac{n(n+1)}{2}}). Step 2: For (n=3), the exponent is (\frac{3\cdot4}{2}=6). Step 3: Diagonal pairs are chosen independently, while non-diagonal pairs are chosen in reverse-pair blocks.

Related tags

Counting Symmetric RelationsRelationsClass 12 MathSymmetric RelationRelations And FunctionsMathematicsClass 12 Mcq

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