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On (A={1,2,3}), how many symmetric relations must contain ((1,2))?

Answer and explanation

Correct answer: (2^5)

Step 1: For (3) elements, there are (\frac{3\cdot4}{2}=6) independent groups. Step 2: If ((1,2)) is included, symmetry forces ((2,1)), fixing one group. Step 3: The remaining (5) groups are free, so the count is (2^5).

Related tags

Fixed PairCounting Symmetric RelationsClass 12Symmetric RelationRelations And FunctionsMathematicsClass 12 Mcq

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