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Is (f:\mathbb{R}\to\mathbb{R}), where (f(x)=\lfloor x\rfloor), onto or not?

Answer and explanation

Correct answer: No because only integer values are attained

Step 1: (\lfloor x\rfloor) is always an integer. Step 2: The codomain (\mathbb{R}) contains non-integers like (\frac{1}{2}), which are not attained. Step 3: Being defined everywhere and being onto are different ideas.

Related tags

Floor FunctionNot OntoInteger RangeReflexive RelationRelations And FunctionsMathematicsClass 12 Mcq

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