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Let (f:A\to B) be onto and (g:B\to C) be onto. What is correct about (g\circ f:A\to C)?

Answer and explanation

Correct answer: (g\circ f) is onto

Step 1: Take any (z\in C). Step 2: Since (g) is onto, (g(y)=z) for some (y\in B), and since (f) is onto, (f(x)=y) for some (x\in A). Step 3: Thus ((g\circ f)(x)=z), so the composition is onto.

Related tags

CompositionOnto FunctionSurjective ProofReflexive RelationRelations And FunctionsMathematicsClass 12 Mcq

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