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If (f:\mathbb{R}\to[-1,1]) where (f(x)=\sin x), what is the correct statement about (f)?

Answer and explanation

Correct answer: (f) is onto but not one-one

Step 1: The range of (\sin x) is ([-1,1]). Step 2: The codomain is also ([-1,1]), so the function is onto. Step 3: Since (\sin x) is periodic, different inputs can give the same output.

Related tags

Trigonometric FunctionOnto But Not One OneSine RangeReflexive RelationRelations And FunctionsMathematicsClass 12 Mcq

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