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Let (f:\mathbb{R}\to[0,\infty)) be defined by (f(x)=x^2+2x+1). When will (f) be considered onto?

Answer and explanation

Correct answer: When codomain remains ([0,\infty))

Step 1: (f(x)=(x+1)^2), so its range is ([0,\infty)). Step 2: The codomain is also ([0,\infty)), so every codomain element is attained. Step 3: In exams, first find the range and then compare it with the codomain.

Related tags

Onto FunctionSurjective FunctionRange CodomainClass 12 Relations FunctionsReflexive RelationRelations And FunctionsMathematicsClass 12 Mcq

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