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On (A={1,2,3,4,5,6}), (R={(a,b):a-b\text{ is divisible by }6}). What is the basis for (R) being reflexive?

Answer and explanation

Correct answer: For every (a), (a-a=0) and (0) is divisible by (6)

Step 1: For reflexivity, check ((a,a)). Step 2: Then (a-a=0), and (0) is divisible by (6). Step 3: In difference-divisibility relations, the diagonal difference is always zero.

Related tags

Reflexive RelationDivisibilityDifferenceRelations And FunctionsMathematicsClass 12 Mcq

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