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If (R) and (S) are both reflexive on (A), which middle element works to show (S\circ R) is reflexive?

Answer and explanation

Correct answer: The same element (a)

Step 1: Reflexivity of (R) gives (aRa). Step 2: Reflexivity of (S) gives (aSa). Step 3: Taking the middle element as (a), we get (a(S\circ R)a), so the composition is reflexive.

Related tags

Composition Of RelationsReflexive PropertyAdvancedHardReflexive RelationRelations And FunctionsMathematicsClass 12 Mcq

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