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If a relation on a 3-element set must be reflexive and must contain exactly 5 pairs, how many such relations are possible?

Answer and explanation

Correct answer: 6

Step 1: Reflexivity fixes the 3 diagonal pairs. Step 2: To have exactly 5 pairs, choose 2 more from the 6 non-diagonal pairs. Step 3: The count is (\binom{6}{2}=15), so none of the listed numerical choices is correct.

Related tags

RelationsFunctionsReflexive RelationCombination CountRelations And FunctionsMathematicsClass 12 Mcq

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