If (f:R\to R), (f(x)=x^3-7), what is (f^{-1}(x))?यदि (f:R\to R), (f(x)=x^3-7), तो (f^{-1}(x)) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\sqrt[3]{x+7})(\sqrt[3]{x+7})
Step 1: Write (y=x^3-7). Step 2: Then (x^3=y+7), so (x=\sqrt[3]{y+7}). Step 3: Replacing (y) by (x), (f^{-1}(x)=\sqrt[3]{x+7}).चरण 1: (y=x^3-7) लिखें। चरण 2: (x^3=y+7), इसलिए (x=\sqrt[3]{y+7})। चरण 3: (y) को (x) से बदलने पर (f^{-1}(x)=\sqrt[3]{x+7})।
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