0 reads0 ratings0 helpful
If (f(x)=x^2-9) and (g(x)=\sqrt{x+9}), what is ((g\circ f)(x))?यदि (f(x)=x^2-9) और (g(x)=\sqrt{x+9}), तो ((g\circ f)(x)) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\sqrt{x^2})(\sqrt{x^2})
Step 1: ((g\circ f)(x)=g(f(x))). Step 2: Put (x^2-9) in place of (x) in (g). Step 3: (g(f(x))=\sqrt{(x^2-9)+9}=\sqrt{x^2}).चरण 1: ((g\circ f)(x)=g(f(x))) है। चरण 2: (g) में (x) के स्थान पर (x^2-9) रखें। चरण 3: (g(f(x))=\sqrt{(x^2-9)+9}=\sqrt{x^2})।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
