If \(f(x)=x+2\), \(g(x)=2x-1\), and \(h(x)=x^2\), what is the value of \((h\circ g\circ f)(1)\)?

Correct answer: 25

Composition is applied from the inside out. Step 1: \(f(1)=1+2=3\). Step 2: apply \(g\) to that result: \(g(3)=2\cdot3-1=5\). Step 3: apply \(h\): \(h(5)=5^2=25\). So the value is 25. The closest wrong choice 16 often arises from an arithmetic/order mistake (for example getting 4 instead of 5 and then squaring); avoid that by writing intermediate results. Exam tip: evaluate one function at a time and record each intermediate value to prevent order errors.