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If (f(x)=\frac{x+2}{x^2-4}), what is the real domain?यदि (f(x)=\frac{x+2}{x^2-4}), तो वास्तविक प्रान्त क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (R-{-2,2})(R-{-2,2})
Step 1: The denominator is (x^2-4=(x-2)(x+2)). Step 2: The denominator cannot be zero, so (x\ne2) and (x\ne-2). Step 3: Even if (x+2) cancels, (x=-2) is not valid in the original function.चरण 1: हर (x^2-4=(x-2)(x+2)) है। चरण 2: हर शून्य नहीं हो सकता, इसलिए (x\ne2) और (x\ne-2)। चरण 3: ऊपर (x+2) कट सकता है, फिर भी मूल फलन में (x=-2) मान्य नहीं है।
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