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If (f:R\to[2,\infty)), (f(x)=x^2+2), which statement is correct about (f)?

Answer and explanation

Correct answer: It is onto but not one-one

Step 1: For every (y\ge2), (x=\sqrt{y-2}) or (x=-\sqrt{y-2}) can be chosen, so it is onto. Step 2: (f(1)=f(-1)=3), so it is not one-one. Step 3: Reading the codomain correctly is very important while checking onto.

Related tags

OntoNot One OneQuadratic FunctionCodomainIntroduction To RelationsRelations And FunctionsMathematicsClass 12 Mcq

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