If (f:R\to R), (f(x)=x^2-6x+11), what is the range of (f)?यदि (f:R\to R), (f(x)=x^2-6x+11), तो (f) का परास क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([2,\infty))([2,\infty))
Step 1: Write (x^2-6x+11=(x-3)^2+2). Step 2: Since ((x-3)^2\ge0), (f(x)\ge2). Step 3: The minimum value is (2), so the range is ([2,\infty)).चरण 1: (x^2-6x+11=(x-3)^2+2) लिखें। चरण 2: ((x-3)^2\ge0), इसलिए (f(x)\ge2)। चरण 3: न्यूनतम मान (2) है, इसलिए परास ([2,\infty)) है।
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