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On (A={1,2,3,4,5}), how many pairs are in the smallest equivalence relation containing (R={(1,2),(2,3),(4,5)})?समुच्चय (A={1,2,3,4,5}) पर (R={(1,2),(2,3),(4,5)}) का सबसे छोटा समतुल्यता संबंध कितने युग्मों वाला होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (13)(13)
Step 1: Elements (1,2,3) are connected into one class. Step 2: Elements (4,5) form another class. Step 3: The first class gives (3^2=9) pairs and the second gives (2^2=4), so the total is (13).चरण 1: (1,2,3) एक वर्ग में जुड़ते हैं। चरण 2: (4,5) दूसरा वर्ग बनाते हैं। चरण 3: पहले वर्ग से (3^2=9) और दूसरे से (2^2=4) युग्म मिलते हैं, कुल (13)।
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