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On (A={1,2,3,4}), how many pairs are in (R={(a,b):a-b\equiv0\pmod2})?समुच्चय (A={1,2,3,4}) पर (R={(a,b):a-b\equiv0\pmod2}) में कुल कितने युग्म होंगे?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (8)(8)
Step 1: The difference is even when the two numbers have the same parity. Step 2: In (A), there are (2) odd and (2) even numbers. Step 3: The number of ordered pairs is (2^2+2^2=8).चरण 1: अंतर सम होने के लिए दोनों संख्याओं की समता समान होनी चाहिए। चरण 2: (A) में (2) विषम और (2) सम संख्याएं हैं। चरण 3: क्रमित युग्मों की संख्या (2^2+2^2=8) होगी।
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